ChemistryGeneral Chemistry

Solubility, Temperature, and Crystallization Lab Report Answers

Use the supplied molar-solubility curves to calculate the starting ion concentrations and predict three crystal crops while keeping measured temperatures and crystal shapes tied to the actual lab.

Question

Solubility, Temperature, and Crystallization Lab ReportPlot the molar solubilities below against temperature:Compound | 0 °C | 20 °C | 40 °C | 60 °C | 80 °C | 100 °CNaCl | 5.4 | 5.4 | 5.5 | 5.5 | 5.5 | 5.6NaNO3 | 6.7 | 7.6 | 8.5 | 9.4 | 10.4 | 11.3KCl | 3.4 | 4.0 | 4.6 | 5.1 | 5.5 | 5.8KNO3 | 1.3 | 3.2 | 5.2 | 7.0 | 9.0 | 11.0Place 8.5 g NaNO3 and 7.5 g KCl in 25 mL water and warm until dissolved.1. Assuming a 25 mL solution, calculate its molarity with respect to NaNO3, KCl, NaCl, and KNO3.2. Cool to about 10 °C, filter the first crystals, describe their shape, and identify the compound from the graph.3. Evaporate the filtrate to about half its volume. Record the temperature when the second crop forms, filter hot, describe the crystals, compare them with the first crop, and identify the compound.4. Cool the final filtrate to 10 °C. Describe the third crop, compare it with the earlier crops, and identify the compound.5. Explain whether mixing aqueous NaNO3 and KCl produces a net ionic reaction and why crystals appear only after cooling or evaporation.

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Evidence boundary

The solubility table, starting masses, assumed 25 mL volume, molarity calculations, and ideal crystallization order are supplied or calculable from the exercise. Actual filtration temperature, crystal shapes, crop purity, and deviations from the ideal order require student observations.