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Setting Up a One-Step Unit Conversion: ALEKS Answer

Use 1000 mL/1 L as the missing factor. Milliliters cancel from the denominator, leaving g/L; the calculated value is -4.1 × 10^7 g/L.

Question

Setting up a one-step unit conversionA student sets up the following equation to convert a measurement. (The ? stands for a number the student is going to calculate.) Fill in the missing part of this equation:(-4.1 × 10^4 g/mL) × [missing conversion factor] = ? g/L

Answer

Fill the blank with:

1000 mL1 L\boxed{\frac{1000\ \mathrm{mL}}{1\ \mathrm{L}}}

The starting unit has milliliters in the denominator. To cancel mL\mathrm{mL}, place it in the numerator of the conversion factor and put L\mathrm{L} in the denominator:

(−4.1×104 gmL)×(1000 mL1 L).\left(-4.1\times10^4\ \frac{\mathrm{g}}{\mathrm{mL}}\right) \times\left(\frac{1000\ \mathrm{mL}}{1\ \mathrm{L}}\right).

The mL\mathrm{mL} units cancel, leaving g/L\mathrm{g/L}, exactly the requested target unit. As a calculation check,

?=−4.1×107 g/L.?=-4.1\times10^7\ \mathrm{g/L}.

Evidence boundary

This answer solves the exact (-4.1 × 10^4 g/mL) setup shown in the cited question source. The requested entry is the conversion factor, not merely the computed final number; the sign and coefficient are retained only as a calculation check.

Sources

These references support the concepts and methods used in the explanation above.

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