ChemistryGeneral Chemistry

ALEKS Stoichiometry Answer: Empirical Formula from Percent Composition

A 100 g basis gives about 3.57 mol C and 3.58 mol O. Their smallest whole-number ratio is 1:1, so the empirical formula is CO.

Question

Measurements show that an unknown compound X has the following composition by mass:

Composition by mass

Carbon42.9%
Oxygen57.2%

Write the empirical chemical formula of X. Show the conversion from mass percentages to moles and reduce the mole ratio to the smallest whole numbers. Use appropriate significant figures.

Answer

Use a 100 g sample so that each percentage becomes the same numerical mass in grams.

ElementMass in 100 gMolar massAmount
C42.9 g12.011 g/mol3.57 mol
O57.2 g15.999 g/mol3.58 mol

Now divide both amounts by the smaller value, 3.57 mol:

  • C: 3.57/3.57=1.003.57/3.57=1.00
  • O: 3.58/3.571.003.58/3.57\approx1.00

The smallest whole-number ratio is therefore C:O=1:1\mathrm{C:O}=1:1.

Empirical formula: CO\mathrm{CO}.

Evidence boundary

The calculation assumes the sample contains only carbon and oxygen and that the reported percentages are rounded measurements. Their total is 100.1%, a 0.1-percentage-point rounding difference that does not change the 1:1 mole ratio. The result is an empirical formula only; a molecular formula would require molar-mass data.

Sources

These references support the concepts and methods used in the explanation above.

ALEKS Stoichiometry Empirical Formula Answer | Verla