PhysicsClassical Physics

What Is Work in Physics? Calculate Work on a Lawn Mower

The lawn mower’s horizontal displacement receives work only from the force component parallel to motion, giving approximately 1.54 kJ for the applied force.

Question

A person pushes a lawn mower 25.0 m across level ground while exerting a constant 75.0 N force along the handle, directed 35.0° below the horizontal. How much work does the person’s applied force do on the mower?

Answer

In physics, a constant force does work according to the dot product of force and displacement:

W=Fdcosθ,W=Fd\cos\theta,

where θ\theta is the angle between the force and the displacement.

Here the displacement is horizontal, so

W=(75.0N)(25.0m)cos(35.0).W=(75.0\,\text{N})(25.0\,\text{m})\cos(35.0^\circ). W1.54×103J.W\approx 1.54\times10^3\,\text{J}.

So the person does about 1.54kJ1.54\,\text{kJ} of work on the mower.

Only the component of the force parallel to the displacement contributes. The downward component of the push is perpendicular to the mower’s horizontal displacement and therefore contributes zero work to this calculation.

Evidence boundary

The calculation assumes the applied force is constant and that the mower’s displacement is 25.0 m horizontally on level ground. It computes only the work done by the person’s applied force, not net work by all forces and not metabolic energy expenditure.

Sources

These references support the concepts and methods used in the explanation above.

What Is Work in Physics? Lawn Mower Calculation | Verla