Question
Try to draw the N₂ Lewis structure before watching the video.
N₂ Lewis structure
Each colon is one lone pair. The three lines represent three shared electron pairs. Thus, each nitrogen has one lone pair and a triple bond; the Lewis bond order is 3.
Count and place the electrons
Each nitrogen contributes five valence electrons, so the molecule has 10 valence electrons. A single N–N bond uses two electrons. Giving both atoms three lone pairs would require fourteen electrons in total, which exceeds the available ten. Sharing three pairs instead gives both atoms an octet without adding electrons.
The final accounting is six electrons in the triple bond plus four in the two lone pairs: 6 + 4 = 10. Around either nitrogen, the six bonding electrons and its two nonbonding electrons make an octet. Count a shared pair toward both atoms' octets, but only once in the molecule's total.
Check formal charge
Formal charge equals the neutral atom's valence-electron count minus its nonbonding electrons minus half its bonding electrons. For either nitrogen:
Both formal charges are zero, consistent with a neutral molecule. In the usual localized bonding description, the triple bond contains one σ bond and two π bonds. The Lewis drawing records connectivity and electron pairs; the positions of its dots do not specify measured orbital shapes.
Evidence boundary
This is the standalone N₂ drawing exercise on the cited university tutorial page. The answer uses a Lewis electron-pair model for neutral nitrogen; it does not infer experimental bond lengths or electronic spectra. Watching the source video is not required to use the prompt.
Sources
These references support the concepts and methods used in the explanation above.