MathAlgebra

Lesson 3.4 Solving Complex 1-Variable Equations Answer Key

Solve the complete set of 24 Lesson 3.4 multi-step equations using distribution, like-term collection, exact fractions, and substitution checks.

Question

Lesson 3.4: Solving Complex 1-Variable EquationsSolve each equation.1a. 3x + 4 + 2x + 5 = 341b. 2(x + 1) + 4 = 122a. 1/2(x + 8) - 15 = -32b. 2x - 5 + 3x + 8 = 183a. -185 = -3r - 4(-5r + 8)3b. -5t - 2(5t + 10) = 1004a. -4b - 4(-6b - 8) = 1724b. -3p + 2(5p - 12) = -735a. -3f + 3(-3f + 5) = -815b. -43 = -5c + 4(2c + 7)6a. -5s + 3(5s + 2) = 1266b. 4d + 2(4d + 7) = -1067a. 103 = -2u + 3(-3u + 5)7b. -2n + 2(3n + 14) = -208a. -11 = 5y + 4(-y - 4)8b. -5a - 2(-7a - 10) = 1289a. 1/2(c + 5) - 10 = -49b. -4f + 1/2(4f - 5) = -1910a. 2(v + 4) + 6 = 2410b. -9 = 6h + 3(-h - 3)11a. -6p - 8(4p + 8) = 9811b. 7c + 3(3c + 5) = -10312a. -4s + 2(4s + 1) = 12512b. -3n + 3(4n + 15) = -21

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Evidence boundary

The equations are reconstructed from the indexed Lesson 3.4 exercise and independently solved by substitution. The linked textbook sources support the solving method, not the wording or numbering of this worksheet.