Inequality for Absolute Value: Solve |4x + 1| − 3 > 2 Graphically

Solve the following inequality using a graphing utility:

$$|4x+1|-3>2.$$

Enter $Y_1=|4x+1|-3$ and $Y_2=2$. Use the absolute-value command (MATH → Num → 1:abs on the textbook's calculator) and locate the intersections (2nd → CALC → 5:intersection; select the first curve, second curve, and a guess). Provide a sketch of both graphs, shade the solution on the x-axis, and give the final solution in interval notation.