PhysicsClassical Physics

How to Find Tension Force: Two Ropes Holding a 76 kg Performer

Use the original 15°/10° rope geometry and a free-body diagram to calculate both tensions supporting a 76.0 kg circus performer.

Question

After a mishap, a 76.0-kg circus performer clings to a trapeze, which is being pulled to the side by another circus artist, as shown here. Calculate the tension in the two ropes if the person is momentarily motionless. Include a free-body diagram in your solution.

Figure geometry: T₁ points upward and left, 15° from the vertical. T₂ points upward and right, 10° above the horizontal. Weight w points vertically downward.

Original OpenStax trapeze figure: T1 at 15 degrees from vertical and T2 at 10 degrees above horizontal

Original figure: OpenStax / Rice University, University Physics Volume 1, Chapter 6 Problem 30, CC BY 4.0. Source.

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Evidence boundary

This solution follows OpenStax University Physics Volume 1, Chapter 6, Problem 30 and its official figure: T₁ is 15° from vertical and T₂ is 10° above horizontal. It uses the intended static-equilibrium idealization, g = 9.80 m/s², and negligible trapeze and rope masses. “Momentarily motionless” only states zero instantaneous velocity; if acceleration is nonzero, the supplied information would not uniquely determine the tensions. The calculated values are conditional on equilibrium.