MathCalculus

Evaluate the Line Integral by Applying Green's Theorem: Four Closed Curves

Applying Green's theorem to four closed curves gives ∫_C 2xy dx+(x+y)dy = −1/60 over the region between y=x³ and y=x, 32/3 between y=0 and y=4−x², 0 on the ellipse x=4+2cosθ, and 1/12 between y=x and y=√x.

Question

For the following exercises, evaluate the line integrals by applying Green's theorem.

  1. ∫C2xy dx+(x+y) dy\displaystyle \int_{C} 2xy\,dx + (x+y)\,dy, where CC is the path from (0,0)(0,0) to (1,1)(1,1) along the graph of y=x3y=x^{3} and from (1,1)(1,1) to (0,0)(0,0) along the graph of y=xy=x oriented in the counterclockwise direction.

  2. ∫C2xy dx+(x+y) dy\displaystyle \int_{C} 2xy\,dx + (x+y)\,dy, where CC is the boundary of the region lying between the graphs of y=0y=0 and y=4−x2y=4-x^{2} oriented in the counterclockwise direction.

  3. ∫C2arctan⁡ ⁣(yx)dx+ln⁡(x2+y2) dy\displaystyle \int_{C} 2\arctan\!\left(\frac{y}{x}\right)dx + \ln(x^{2}+y^{2})\,dy, where CC is defined by x=4+2cos⁡θ, y=4sin⁡θx=4+2\cos\theta,\ y=4\sin\theta oriented in the counterclockwise direction.

  4. ∫Csin⁡xcos⁡y dx+(xy+cos⁡xsin⁡y) dy\displaystyle \int_{C} \sin x \cos y\,dx + (xy + \cos x \sin y)\,dy, where CC is the boundary of the region lying between the graphs of y=xy=x and y=xy=\sqrt{x} oriented in the counterclockwise direction.

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Evidence boundary

This page is a normalized presentation of the OpenStax Calculus Volume 3 section 6.4 exercise set “evaluate the line integrals by applying Green's theorem.” Items 146 to 149 are reproduced as published, with the complete vector field, the closed curve and the counterclockwise orientation kept for each one. Two items of the same set are not used: item 150 fixes the two bounding circles but leaves the orientation of the inner circle ambiguous, and item 151 does not say which semicircular arc is meant, so neither has a single determinate answer. The results are those of the stated curves only, and no claim is made about integrals over other paths joining the same endpoints.