StatisticsInferential Statistics

Knowledge guide

How Confidence Level Changes a Proportion Interval

A one-proportion interval combines a sample proportion, its estimated standard error, and a confidence-level critical value. Higher confidence increases the margin of error and widens the interval.

A proportion interval starts with a point estimate

Suppose a random sample contains xx observations with a characteristic out of nn total observations. The sample proportion

p^=xn\hat p=\frac{x}{n}

is the point estimate of the unknown population proportion pp. For the usual one-sample normal-approximation interval, the estimated standard error is

SE=p^(1p^)n.SE=\sqrt{\frac{\hat p(1-\hat p)}{n}}.

A confidence interval has the general form

p^±zSE,\hat p\pm z^*SE,

where zz^* is the standard-normal critical value associated with the selected confidence level.

Higher confidence means a wider interval

With the sample fixed, p^\hat p, nn, and the standard error do not change. Raising the confidence level increases zz^*, which increases the margin of error and widens the interval.

For example, suppose 232 of 400 sampled students use a campus tutoring service. Then

p^=232400=0.58,SE=(0.58)(0.42)4000.02468.\hat p=\frac{232}{400}=0.58, \qquad SE=\sqrt{\frac{(0.58)(0.42)}{400}}\approx0.02468.

The 90% interval is approximately

0.58±1.645(0.02468)=(0.539,0.621),0.58\pm1.645(0.02468)=(0.539,0.621),

while the 95% interval is approximately

0.58±1.960(0.02468)=(0.532,0.628).0.58\pm1.960(0.02468)=(0.532,0.628).

The 95% procedure pays for greater long-run capture by producing a wider range.

Interpret confidence as a property of the procedure

A practical interpretation is: “We are 95% confident that the population proportion lies between the two endpoints.” The repeated-sampling meaning is more precise: if the same sampling-and-interval procedure were repeated many times, about 95% of the resulting intervals would contain the fixed population proportion.

It is not correct to say that 95% of individual observations lie inside the interval. The interval estimates a population proportion, not the spread of individual data.

Check the conditions before generalizing

The normal approximation needs enough expected successes and failures for the sampling distribution of p^\hat p to be approximately normal. The observations should also come from a random or otherwise defensibly representative process and be sufficiently independent.

When counts are small or sampling is biased, arithmetic alone does not rescue the inference. A different interval method or a better data-collection design may be needed.

Related question

Apply this knowledge

Use the concept guide to understand the reasoning, then return to the complete question and worked answer.

MyLab Statistics Answer Key: 90% and 95% Confidence Intervals

Sources

These references support the core concepts and interpretation boundaries explained above.

How Confidence Level Changes a Proportion Interval | Verla