MathCalculus

Related Rates Calculus: Current Change as Voltage Falls and Resistance Rises

Find the instantaneous current rate when voltage falls and resistance rises.

Question

In a simple circuit V=IRV=IR, with VV in volts, II in amperes, and RR in ohms. When R=400 ΩR=400\ \Omega and I=0.04 AI=0.04\ \mathrm A, voltage is decreasing at 0.03 V/s0.03\ \mathrm{V/s} and resistance is increasing at 0.03 Ω/s0.03\ \Omega/\mathrm s. Find the instantaneous rate of change of current in amperes per second.

This question has been answered.

Explore the full answer and supporting references to better understand this question.

Verla BasicBest value

$19.99/month

  • Everything in Study Pass
  • Assignments with writing output
  • AI detection and humanizer
  • Basic quotas across every tool
Study Pass

$0.99/month

  • Entire question library
  • Knowledge guides and sources
  • Detailed answers and explanations
  • No AI tools or quotas

Evidence boundary

The rates are instantaneous at the same moment as R = 400 Ω and I = 0.04 A. Decreasing voltage means −0.03 V/s; increasing resistance means +0.03 Ω/s. This uses the 2024 publisher PDF version.